3m^2=-2m+87

Solution for 3m^2=-2m+87 equation:

3m^2=-2m+87

We move all terms to the left:

3m^2-(-2m+87)=0

We get rid of parentheses

3m^2+2m-87=0

a = 3; b = 2; c = -87;
Δ = b2-4ac
Δ = 22-4·3·(-87)
Δ = 1048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1048}=\sqrt{4*262}=\sqrt{4}*\sqrt{262}=2\sqrt{262}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{262}}{2*3}=\frac{-2-2\sqrt{262}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{262}}{2*3}=\frac{-2+2\sqrt{262}}{6}
$